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We can generalize from twins to triples.
Skinny triples. AKA 2 x 3 circles.
Imagine we have:
1 2 3 4 5 6 7 8 9
.---------.---------.---------..---------.---------.---------..---------.---------.---------.
a | | | || | | || | | | a
b | | | || | | || | | | b
c | | | || | | || | | | c
|---------+---------+---------++---------+---------+---------++---------+---------+---------|
d | | | || 2 4 | 4 7 | 2 7 || | | | d
e | | | || | | || | | | e
f | | | || | | || | | | f
|---------+---------+---------++---------+---------+---------++---------+---------+---------|
g | | | || | | || | | | g
h | | | || | | || | | | h
i | | | || | | || | | | i
'---------'---------'---------''---------'---------'---------''---------'---------'---------'
1 2 3 4 5 6 7 8 9
d4 = 2 iff d6 = 7 iff d5 = 4.
d4 = 4 iff d5 = 7 iff d6 = 2.
so in either case all the digits 2,4,7
are monopolized by d4, d5, and d6.
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