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  Fat triplets.  AKA 3 x 3 circles.
  
  Imagine we have:
  

1 2 3 4 5 6 7 8 9 .---------.---------.---------..---------.---------.---------..---------.---------.---------. a | | | || | | || | | | a b | | | || | | || | | | b c | | | || | | || | | | c |---------+---------+---------++---------+---------+---------++---------+---------+---------| d | | | || 2 4 7 | 2 4 7 | 2 4 7 || | | | d e | | | || | | || | | | e f | | | || | | || | | | f |---------+---------+---------++---------+---------+---------++---------+---------+---------| g | | | || | | || | | | g h | | | || | | || | | | h i | | | || | | || | | | i '---------'---------'---------''---------'---------'---------''---------'---------'---------' 1 2 3 4 5 6 7 8 9

How to analyze rigorously? (The iff argument gets messy.) digits 2 4 7 | possibilities ------- | cells 2 4 7 | 2 2 4 4 7 7 2 4 7 | 4 7 2 7 2 4 2 4 7 | 7 4 7 2 4 2 so in all cases all the digits 2,4,7 are monopolized by d4, d5, and d6.

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