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Fat triplets. AKA 3 x 3 circles.
Imagine we have:
1 2 3 4 5 6 7 8 9
.---------.---------.---------..---------.---------.---------..---------.---------.---------.
a | | | || | | || | | | a
b | | | || | | || | | | b
c | | | || | | || | | | c
|---------+---------+---------++---------+---------+---------++---------+---------+---------|
d | | | || 2 4 7 | 2 4 7 | 2 4 7 || | | | d
e | | | || | | || | | | e
f | | | || | | || | | | f
|---------+---------+---------++---------+---------+---------++---------+---------+---------|
g | | | || | | || | | | g
h | | | || | | || | | | h
i | | | || | | || | | | i
'---------'---------'---------''---------'---------'---------''---------'---------'---------'
1 2 3 4 5 6 7 8 9
How to analyze rigorously?
(The iff argument gets messy.)
digits 2 4 7 | possibilities
------- |
cells 2 4 7 | 2 2 4 4 7 7
2 4 7 | 4 7 2 7 2 4
2 4 7 | 7 4 7 2 4 2
so in all cases all the digits 2,4,7
are monopolized by d4, d5, and d6.
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